Hi I want to list filenames in a directory having timestamp in its file name. For example: gn_752_pos_id_n_00_000_9_20200331.dat.gz gn_40006_dep_ip_c_qa_500_2_20200331_20200622T082432.dat.gz
So I want to get a list of files having timestamp format like '20200622T082432'.
I tried the following command but it didn't work. find . -type f | xargs ls -l --time-style="yyyyMMdd'T'HHmmss"
I think you want to glob files whose name contains the pattern:
8 digits T 6 digits
You can do that like this:
ls *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]T[0-9][0-9][0-9][0-9][0-9][0-9]*
In practice, that is rather unwieldy, so you might define an alias:
alias ts='ls *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]T[0-9][0-9][0-9][0-9][0-9][0-9]*'
Then you can just use:
ts
Or, you might find that a less rigorous test requiring only a single digit either side of T is enough for most purposes:
ls *[0-9]T[0-9]*
You could also leverage a "regular expression" with a specific number of repetitions (i.e. 8 digits, T, 6-digits) like this GNU find:
find . -regextype posix-extended -regex ".*[0-9]{8}T[0-9]{6}.*"
