Is there any way to replace/substitute an array data points in uint8 data

Question

I have this data

old= array([[171, 171, 171, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       ...,
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17]], dtype=uint8)

in this data i need to put my external array data points

new= array([ 65, 108, 105,  32, 105, 115,  32, 116, 104, 101,  32,  66, 101,
       115, 116,  32, 105, 110,  32, 116, 104, 101,  32, 119, 111, 114,
       108, 100,  32, 121, 101, 101, 104, 104, 104, 104, 104, 104, 104,
       104])

in the first row of the old array such that output is like

 old= array([[  65, 108, 105,  32, 105, 115,  32, 116, 104, 101,  32,66,101,
       115, 116,  32, 105, 110,  32, 116, 104, 101,  32, 119, 111, 114,
       108, 100,  32, 121, 101, 101, 104, 104, 104, 104, 104, 104, 104,
       104, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       ...,
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17]], dtype=uint8)

Have you read the `numpy` docs about indexing? How would you display the first 40 values of the first row of `old`? — hpaulj, Jun 15 '20 at 19:19

score 1 · Answer 1 · answered Jun 15 '20 at 18:55

1

To replace the first row of your array:

old[0] = new

answered Jun 15 '20 at 18:55

badarots

36
2

score 0 · Answer 2 · answered Jun 15 '20 at 18:49

0

I'm assuming you are using numpy? Does

old[0] = new[0]

work? (Assuming you wanted to replace the first row of the old array with the first row of the new array)

answered Jun 15 '20 at 18:49

digital_hog

202
1
11

Quang Hoang · Accepted Answer · 2020-06-15T19:49:47.760

0

This should do:

old[0, :len(new)] = new

edited Jun 15 '20 at 19:49

answered Jun 15 '20 at 19:23

Quang Hoang

146,074
10
56
74

see the question not slicing i want to substitute values of of new array in old's first row array – Zewo Jun 15 '20 at 19:43
That's what `= new` is for, is it not? – Quang Hoang Jun 15 '20 at 19:50
i dont know what are u saying.....but this ur answer is not working for me – Zewo Jun 15 '20 at 19:54
my bad.. i m extremely sorry .. that was amaxing.. can u explain this to me sir? – Zewo Jun 15 '20 at 20:04
1

As you said, it's simply slicing. However, numpy allows new values assignment with slicing just as the code shows. – Quang Hoang Jun 15 '20 at 20:05
why we cant use replace in pyhton ? – Zewo Jun 15 '20 at 20:07

Is there any way to replace/substitute an array data points in uint8 data

3 Answers3