Stubbing a method on a spyk object calls the original method immediately

Question

for example the method

   class SomeClass() {
       fun login(listener: (Boolean) -> Unit ) {
            do some async logic and then call the listener with the result
      }
   }

   val spy = spyk(SomeClass())  {

          val completion = slot<(Boolean) -> Unit>()
         //this immediately calls the original login method
         every { login(capture(completion)) } answers {
              completion.captured.invoke(true)
         }
     }

trying to stub the login method immediately invokes it.

Do you know how to just stub it and not invoke it?

score 0 · Answer 1 · answered Jun 11 '20 at 19:10

0

If we look at the Mockk, maybe relaxed-mock ?

answered Jun 11 '20 at 19:10

MaTriXy

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i do not see an option to put relaxed on a spy. I do not need a mock, I need a spy, i want to mock partial functionality and keep the rest original – Lena Bru Jun 12 '20 at 05:19
i used relaxed mock and got the same result – Lena Bru Jun 26 '20 at 15:17

Stubbing a method on a spyk object calls the original method immediately

1 Answers1