Is there any way to call a class member function that takes only 1 template argument instead of 2?
I would like to write some code like this:
template<typename T, size_t N>
void Container<int, N>::quick_sort() {
}
Is there any way to call a class member function that takes only 1 template argument instead of 2?
I would like to write some code like this:
template<typename T, size_t N>
void Container<int, N>::quick_sort() {
}
You cannot partial specialize a method, you could partial specialize the whole class, but require some duplication.
template<typename T, size_t N>
class Container
{
// Some code ...
void quick_sort();
};
template <typename T,size_t N>
void Container<T, N>::quick_sort()
{
// ...
}
// Class specialization
template <size_t N>
class Container<int, N>
{
// Some similar/same code...
void quick_sort();
};
template <size_t N>
void Container<int, N>::quick_sort()
{
// ...
}
As alternative, C++17 allows
template<typename T, size_t N>
class Container
{
// Some code ...
void quick_sort()
{
if constexpr (std::is_same_v<int, T>) {
// ...
} else {
// ...
}
}
};
For prior versions, regular if
would probably produces error (both branches should be valid, even if not taken).
So tag dispatching is an easy approach (SFINAE is another one):
template <typename> struct Tag{};
template<typename T, size_t N>
class Container
{
private:
void quick_sort(tag<int>)
{
// ...
}
template <typename U>
void quick_sort(tag<U>)
{
// ...
}
public:
void quick_sort()
{
quick_sort(Tag<T>());
}
// Some code ...
};