How to call "QList QVariant::toList () const"

Question

This is a pretty simple and probably dumb question, but I have forgotten how to use QList QVariant::toList () const

QVariant s = this->page()->mainFrame()->evaluateJavaScript (QString ("Open(%1,%2)").arg (point.x()).arg (point.y()));

List<QVariant> x;
x = s.toList ();

Of course this is wrong, what is the correct way out? :redface:

score 2 · Accepted Answer · answered Jun 03 '11 at 11:12

2

What you do is almost correct:

QList<QVariant> x = s.toList();

(Note the use of QList instead of List.)

answered Jun 03 '11 at 11:12

mtvec

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That was a "typo" from my side. The actual code contains QList. – Aquarius_Girl Jun 03 '11 at 11:13
No it is not, it is producing errors which I'll soon post in OP. – Aquarius_Girl Jun 03 '11 at 11:18
:banghead: That code is correct indeed, the long errors which I was getting were due to the way I was using it:` if (x.isEmpty() == false) { for (int i = 0; i < 49; i++) std :: cout << "\n-----------" << x[i]; }` – Aquarius_Girl Jun 03 '11 at 11:26

score 1 · Answer 2 · answered Jun 03 '11 at 11:11

1

What you're doing is right. May be you can check if the variant contains a list before converting it. E.g:

QVariant variant = list;
if(variant.canConvert(QVariant::List))
{
    QList<QVariant> list_1 = variant.toList();
}

answered Jun 03 '11 at 11:11

Chandan

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How to call "QList QVariant::toList () const"

2 Answers2