How to solve factorial even numbers on the n number, then multiply them

Question

For example there are 3 then the program will multiplying the first 3 factorials 2 x 4 x 6 = 48. For example if the user wants 3 then the program will multiply the first 3 factorials only and the sum value will decrease if the initial value is even. type int which contains a lot of even numbers that are wanted and will continue to grow in each recursive

Call:

Print (Value (number, initial))
print(value(3,0))

Output:

Explanation:

The first 3 even values are 2,4,6. So the results of their multiplication will be yield 48.

Sorry but what is wrong with my program:

def value(number,initial):

    while(initial<=(number)):

        print((initial*2), end="")

        initial = (initial+1)

        print("%d *" %(initial),end='')

        return initial * (str(value(number,initial)))


value(3,0)

Could you declare what does the second parameter do in your code? — jizhihaoSAMA, Jun 04 '20 at 16:57
It aims to fill in the amount is 3 and the beginning is 0 (always 0 when the program starts) — Yeni Eldima, Jun 04 '20 at 17:00
Yah right, and how to multiply it, because it starts from 0 and multiplied by 0 then all results are 0 — Yeni Eldima, Jun 04 '20 at 17:08
`lambda` represents the operation of two elements in the list. — jizhihaoSAMA, Jun 05 '20 at 01:01

score 2 · Accepted Answer · answered Jun 04 '20 at 17:15

How about using reduce?

You could generate a range which full with the number starts with initial and the amount is the number

from functools import reduce

def value(number, initial):
    return reduce(lambda x, y: x * y, range(initial + 2, (initial + 2) + 2 * number, 2))

print(value(3, 0))
# 48

How to solve factorial even numbers on the n number, then multiply them

1 Answers1