Error calculating time difference in Python

Question

Quick question. Does someone know why I'am getting an 'Invalid Syntax' error usign this code? Thank you all.

def get_time_difference(date, time_string):
    time_difference = datetime.now() - datetime.strptime(f"{date} {time_string}", "%d-%m-%Y %H:%M")
    return f"{time_difference.hour}:{time_difference.minute}"


get_time_difference(1-1-2020 1:50)

Thank you both, I received an other error which got fixed by @Edison Feneyab — ManCity10, Jun 02 '20 at 12:04

score 4 · Accepted Answer · answered Jun 02 '20 at 12:02

You should call get_time_difference("1-1-2020", "1:50").

However, you will get another error:

AttributeError: 'datetime.timedelta' object has no attribute 'hour'

You can adapt get_time_difference as follows:

def get_time_difference(date, time_string):
    time_difference = datetime.now() - datetime.strptime(
        f"{date} {time_string}", "%d-%m-%Y %H:%M"
    )
    hours = time_difference.seconds // 3600
    minutes = time_difference.seconds // 60 % 60
    return f"{hours}:{minutes}"

score 1 · Answer 2 · answered Jun 02 '20 at 12:12

1

from datetime import datetime


def get_time_difference(date, time_string):
    time_difference = datetime.now() - datetime.strptime(f"{date} {time_string}", "%d-%m-%Y %H:%M")
    return f"{time_difference.seconds // 3600}:{time_difference.seconds // 60 % 60}"


print(get_time_difference('1-1-2020', '1:50'))

Output

15:50

answered Jun 02 '20 at 12:12

Shivam Bharadwaj

1,864
21
23

Thank you this worked fine. Where does the f actually stand for in the code? – ManCity10 Jun 02 '20 at 12:27
This f is just for formatting, otherwise you can also return `str(time_difference.seconds // 3600) + ":" + str(time_difference.seconds // 60 % 60)` – Shivam Bharadwaj Jun 02 '20 at 14:00

Error calculating time difference in Python

2 Answers2