I have been experiencing this NOT ADirectory Error while running a code in Python

Question

The ERROR

Traceback (most recent call last):
  File "images.py", line 11, in <module>
    for filename in os.listdir(path):
NotADirectoryError: [Errno 20] Not a directory: 'images.py'

I m using this code but the above error keeps coming, don't know what to do next?

This is my code

import sys
import os
from PIL import Image

image_folder = sys.argv[0]
output_folder = sys.argv[1]

if not os.path.exists(output_folder):
   os.makedirs(output_folder)

for filename in os.listdir(image_folder):
  img= Image.open(f'{image_folder}{filename}')
  img.save(f'{output_folder}{filename}','png')
  print('alldone!')

Please copy/paste exactly how you run this from the command line. The error lies in `image_folder = sys.argv[0]`. Print out `image_folder` and `output_folder` in your script to see what I mean — inspectorG4dget, Jun 01 '20 at 06:10
The first element in `sys.argv` (`sys.argv[0]`) is the path of the script, not a path of a directory — בנימין כהן, Jun 01 '20 at 06:12
``sys.argv[1]`` get's the first command line argument where as ``sys.argv[0]`` get's the file name. — sushanth, Jun 01 '20 at 06:12
inspectorG4dget i tried but it says Traceback (most recent call last): File "images.py", line 6, in output_folder = sys.argv[2] IndexError: list index out of range — Rishabh Jain, Jun 01 '20 at 06:25

score 0 · Accepted Answer · answered Jun 01 '20 at 06:16

0

The first element of your script arguments, sys.argv[0], is the path of the file executed - images.py in your case.

Change:

image_folder = sys.argv[0]
output_folder = sys.argv[1]

To:

image_folder = sys.argv[1]
output_folder = sys.argv[2]

answered Jun 01 '20 at 06:16

Gabio

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I tried this one but it says – Rishabh Jain Jun 01 '20 at 06:24
Traceback (most recent call last): File "images.py", line 6, in output_folder = sys.argv[2] IndexError: list index out of range – Rishabh Jain Jun 01 '20 at 06:24
When i run the above one it says – Rishabh Jain Jun 01 '20 at 06:29
images.py image-playground/new/ #IT works but second one don't. @Gabip – Rishabh Jain Jun 01 '20 at 06:29
@RishabhJain did you provide 2 arguments for the script as the code requires? please share how you run your script. – Gabio Jun 01 '20 at 06:33
I ran it again through different technique it worked @Gabip – Rishabh Jain Jun 01 '20 at 07:02
Although another while running the code further i m shown this error: "cannot identify image file %r" % (filename if filename else fp) PIL.UnidentifiedImageError: cannot identify image file 'image-playground/.DS_Store' – Rishabh Jain Jun 01 '20 at 07:04
@RishabhJain this error is unrelated to your original topic. Please consider asking it as another SO question. – Gabio Jun 01 '20 at 07:44

I have been experiencing this NOT ADirectory Error while running a code in Python

1 Answers1