How to print a string before using "*" to unpack list

Question

Is it possible to print a string before using the * operator when unpacking a tuple:

m = ['b', 'a', 'e']
print(*m, sep = ',')

b, a, e

I tried to print something before it:

print("String: " + *m, sep = ",")

My desired output would be:

String: b, a, e

Is it possible to have a string print before this, and what would be the correct syntax?

deceze, is it possible to print that without the comma being after the string, and only having the comma apply to the items in the list? — ter123, May 29 '20 at 10:12

score 1 · Accepted Answer · answered May 29 '20 at 10:12

*m unpacks the list m into separate arguments. It's equivalent to:

print('b', 'a', 'e')

You can add additional arguments before and after that:

print('string', *m, sep=',')

is it possible to print that without the comma being after the string, and only having the comma apply to the items in the list?

Take your pick:

print(f'String: {", ".join(m)}')

print('String:', ', '.join(m), sep=' ')

print('String:', end=' ')
print(*m, sep=', ')

score 0 · Answer 2 · edited May 30 '20 at 00:49

0

Try using this code:

print(",".join(m))

edited May 30 '20 at 00:49

the Tin Man

answered May 29 '20 at 10:05

kaamkar

It helps more if you supply an explanation why this is the preferred solution and explain how it works. We want to educate, not just provide code. – the Tin Man May 30 '20 at 00:46

score -2 · Answer 3 · edited May 30 '20 at 00:49

-2

I think you can use

print(",".join(m))

edited May 30 '20 at 00:49

the Tin Man

answered May 29 '20 at 10:00

lukas.tomoszek

3 Answers3