Is it possible to print variables and change them consequently in Makefile?

Question

I have the following Makefile:

all: print1 print2 

world=world1
print1:
    @echo $(world)

world=world2
print2:
    @echo $(world)

.PHONY: all print1 print2

When running with make I expected to get:

world1
world2

But I got:

world2
world2

Is it possible to get the expected output only with the variable world?

Short answer: no. Are you exploring Make, or do you have a purpose in mind? — Beta, May 27 '20 at 02:49
@Beta yes, I want to run different models (targets) but they have common arguments name like `$(num_layers)` but depending on the target it should be different. — Kenenbek Arzymatov, May 27 '20 at 02:53

score 2 · Accepted Answer · answered May 27 '20 at 03:08

2

print1: world=world1
print1:
    @echo $(world)

print2: world=world2
print2:
    @echo $(world)

And if the recipes are identical, you can combine the rules:

print1: world=world1
print2: world=world2

print1 print2:
    @echo $(world)

answered May 27 '20 at 03:08

Beta

Is it possible to set multiple variables at once like this: ```print1: var1=var1 var2=var2 ``` – Kenenbek Arzymatov May 28 '20 at 01:42
@KenenbekArzymatov: No, but you can put `print1: var1=var1` in one line and `print1: var2=var2` in another. – Beta May 28 '20 at 01:48

1 Answers1