Python - How do I compare an element in a list against other elements in the same list

Asked May 23 '20 at 12:11

Active May 23 '20 at 12:55

Viewed 30 times

For e.g.

lst = [['A', 300, 20], ['B', 235, 10], ['C', 274, 40], ['D', 290, 12]]

Lets just say I want to compare the 2nd element (index 1) of each list and find the highest. I only know how to compare the first list with the next list and so on. Which means I'm not comparing the list with the other lists. How do I start with the first list, compare with the other lists, then move onto the second list and compare with the other lists including the first one etc. So that each list has been compared with the others instead of just looking at the next one. I want to see which list dominates the rest, so for this instance I want to add 'True' to the end of the list.

Output: ['A', 300, 20, True]

edited May 23 '20 at 12:55

asked May 23 '20 at 12:11

wick_7

Please update your question with the output you require. – quamrana May 23 '20 at 12:14
A simple nested loop should help you do the trick – ghost May 23 '20 at 12:14
2

`max([x[1] for x in lst])` – deadshot May 23 '20 at 12:16
2

To get sublist with max 2nd value: `max(lst, key=lambda x: x[1])` which returns ['A', 300, 20] in this case. – DarrylG May 23 '20 at 12:21
@quamrana I have updated it – wick_7 May 23 '20 at 12:55
Finding the maximum does not have to be O(n^2) – Mad Physicist May 23 '20 at 13:00

Python - How do I compare an element in a list against other elements in the same list

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