Halcon - Sort tuple based on list of indices

Question

I have 2 Tuples, representing a list of point coordinates. I need them sorted by row. Following code sorts the rows tuple, and returns a new tuple containing the the change it made in the ordering of the tuple.. Now I would need to use this information to sort the column tuple the same way.

tuple_sort_index (intersection_points_row, Indices)

Indices now contains this: [1, 0, 5, 2, 4, 3]

so I would need to sort intersection_points_col with these values [730.5, 1200.15, 515.429, 670.778, 1330.5, 1473.4] in the same order as displayed in the tuple above..

How can this be done?

score 1 · Accepted Answer · answered May 21 '20 at 07:07

1

Tuple := [730.5, 1200.15, 515.429, 670.778, 1330.5, 1473.4]
Indices := [1, 0, 5, 2, 4, 3]

** Sorted
Sorted := Tuple[Indices]

** Inverted
tuple_inverse (Sorted, Inverted)

answered May 21 '20 at 07:07

Vladimir Perković

1,351
3
12
30

1

thank you very much!! didnt imagine that you can pass indices into an array that way. – sharkyenergy May 21 '20 at 07:13

Halcon - Sort tuple based on list of indices

1 Answers1