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I want to remove @email.com from this string and also as such that even if the "myemail" part is changed the code should still work I did this:

email = "myemail@email.com"
a = a.replace(a[-10:-1],'')
print(a)

Output:

myemailm

I wanted to remove that 'm' as well but i can't find a way to do so.

Thanks in advance.

Anshul Vyas
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Harsh
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7 Answers7

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Your slice is specifically excluding the last character. You're also making things more complicated than they need to be by using both a slice and a replace; any one of these on its own will do the job more simply:

>>> "myemail@email.com"[:-10]
'myemail'
>>> "myemail@email.com".replace("@email.com", "")
'myemail'
>>> "myemail@email.com".split("@")[0]
'myemail'
Samwise
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Find the index of @ and keep the first part

email = "myemail@email.com"
email = email[:email.index('@')]
print(email)

Output:

myemail
rdas
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0

You can try like below:

email = "myemail@email.com"
a = email.split('@')
a[0]
Saniya Parveez
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Or you can make it with a split. 

In [1]: "myemail@email.com".split("@")[0]                                                                                                     
Out[1]: 'myemail'
Martin Nečas
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email = "myemail@email.com"
a = email.split("@")[0]
print(a)

gives output:

myemail

email.split("a") returns a list ["myemail", "email.com"] from which you can take the first element using [0]

YulkyTulky
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You could split the email into a list, using the @ as a separator, then print the first item in the list, which would be everything before the @. This would account for domain names of different length. For example, @yahoo.com is longer than @gmail.com, you'd have to account for the individual lengths.

email = "myemail@email.com"
a = email.split("@")[0]
print(a)

Or you can use the replace method as you are and do it on a case by case basis, but your splice is incorrect. The stop value is not included. So by your saying a = a.replace(a[-10:-1] , '') you haven't replaced the m from .com. If you were to instead say a = a.replace(a[-10:],'') you will replace everything from the -10th index to the end of the string.

Another potential solution would be to find the index of the @. 

a = email[0:email.index('@')]
Brenden Price
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code:

email = "myemail@email.com"

new_email = email.replace(email[-10:],'')

print(new_email)

output: myemail

Labhesh Lalka
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