eq = (((1 - (2 * normal_rpm - s8) ** s1) * s2 * math.sin(normal_rpm ** s3 / s4) * (1 - math.sin((normal_rpm + s5) ** (2) + 5) + s6) / (s7))) + 0.67
is my formula for this variable, where the S variables are floats. this sometimes returns a result like this
(0.6806708980989302+0.008606807113252896j)
I cannot use this result in further math, I need a float, even if I have to round the answer a bit.