`elif` not recognized

Question

I'm trying to use flow control

if x == `Lala´:
    print(`lalalala.´)
    elif != `lala´:
        print (`lololol.´)

The problem I have is a syntax error with - e - from elif and when I skip four spaces at the front or four spaces at the back the problem stills. When I put the elif in the same line as the if the program doesn't execute the elif.

It should be at the same indentation level as the `if`. Note that when the `if` condition is met, nothing else will be done. You've also got a fair amount of syntax errors - you've got "smart" quotes in there, the `elif` only has half of a conditional, the two conditions don't make a lot of sense (on is matching `Lala`, the other is saying not `lala` - looks like a case error), you could probably just use an `else`, etc. — ernie, May 12 '20 at 01:17
Please upvote helpful answers and accept the one that helps you best. — Robert, May 12 '20 at 18:24

score 3 · Answer 1 · answered May 12 '20 at 01:18

You have a few problems.

Whitespace is meaningful in python. The elif needs to be at the same level as the if
Your elif statement is malformed.
Your quote marks are non-standard.

It should be:

if x == 'Lala':
    print('lalalala.')
elif x != 'lala':
    print ('lololol.')

score 1 · Answer 2 · answered May 12 '20 at 01:21

You seem to have quotations marks that are copied out of a text/document file format (e.g. word/pdf). These should be ''.
Remember that elif needs to be on the same indentation level as if in python
You need to have a full condition inside the elif - currently you have != 'lala' - you need to have the full condition = x != 'lala'
Make sure to initialise x as well - although I'll assume you have done this further up in your code

Like this:

if x == "Lala":
    print("lalalala.")
elif x != "lala":
    print ("lololol.")

score 0 · Answer 3 · answered May 12 '20 at 01:19

0

x = 'nothing'
if x == 'Lala' :
    print ('lalalala.')
elif x != 'lala' :
    print ('lololol.')

You forgot to compare x in your elif statement.

answered May 12 '20 at 01:19

bashBedlam

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score 0 · Answer 4 · answered May 12 '20 at 01:20

First you have mixed up your quotes. In both the if and the print you start with a "``" and close with a "´". Programming languages usually don't take typographical quotes (Perl 6 is the only exception I know). If you are using WordPad or Microsoft Word to write code, switch to a programmer editor that doesn't change your quotes. Always use the same character for beginning and end of a text, either " or ' (or even """ or ''' for multi-line strings).

Then your elif needs to be on the same level with the if: they are different branches of the same flow control. With its current indentation you have an elif without a matching if.

You are also missing the variable in the elif comparison: to what do you want to compare "lala"?

Finally you should initialize x before comparing it.

x = "..."

if x == "Lala":
    print("lalalala.")
elif x != 'lala':
    print ('lololol.')

score 0 · Answer 5 · answered May 12 '20 at 01:32

I think the problem you are having here is that it is not formatted properly and your ELIF statement does not have the same indentation level, bear in mind that an ELIF statement should always be on the same level as a regular IF statement. If the IF statement is satisfied before the ELIF statement, your program will not continue to execute any further validation statement.

Recall that the ELIF statement means "else-if" meaning that if the initial IF statement is not satisfied, the program will continue to validate the variable through the ELIF statement. Treat it like it is an ELSE statement, and give it the same indentation level as an IF statement. Also remember that whitespaces are important in Python, so pay particular attention to this as well, I have included the revised code below. Do not forget to include the variable X in your ELIF statement.

So instead of this:

if x == `Lala´:
    print(`lalalala.´)
    elif != `lala´:
        print (`lololol.´)

Do this instead:

if x == 'Lala':
    print('lalalala.')
elif x != 'lala':
    print ('lololol.')

`elif` not recognized

5 Answers5