How to do nested if - else with 4 numbers to find biggest number

Question

public class NastingIfElse {

    public static void main(String[] args) {

        int a = 998 , b = 857 , c = 241 , d = 153;
        int result;

        if ( a > b ) {
            if ( a > c ) {
                if ( a > d ) {
                    result = a;
                }else {
                    result = d;
                }
            }
        }
        if ( b > c ) {
            if ( b > d ) {
                result = b;
            }else {
                result = d;
            }
        }
        if ( c > a ) {
            if ( c > d ) {
                result = c;
            }else {
                result = d;
            }
        }
        if ( d > a ) {
            if ( d > c ) {
                if ( d > b ) {
                    result = d;
                }else {
                    result = b;
                }
            }
        }



        System.out.println("Biggest number of three is " + result);


    }

}

I want to do this code and find out the biggest number from this 4 numbers. but have some problems with this "nesting if program". so I need to find out some way to run this particular program for finding the highest number from these numbers by only using "nested if".

so help me in this program.

You could replace all that with: `Math.max(Math.max(Math.max(a,b),c), d);` If you had an arbitrary list of numbers, you could do that in a loop, `Math.max(max_of_last_pair, current_number);`. — lurker, May 11 '20 at 16:11
"but have some problems" => And why don't you tell us what problems you have? — Seelenvirtuose, May 11 '20 at 16:17
By the way, your output should probably read, `"Biggest number of four is "`. :) — lurker, May 11 '20 at 16:17
Is it a practice from a lesson that "must" be done by nested if and elses? — Majid Roustaei, May 11 '20 at 16:19

score 0 · Accepted Answer · answered May 11 '20 at 16:26

if it is some kind of practice which must be done by nested if and elses, try this:

    int a = 998 , b = 857 , c = 241 , d = 153;
    int result;

    if ( a > b ) {
        if ( a > c ) {
            if ( a > d ) {
                result = a;
            }
            else {
                result = d;
            }
        }
        else if ( c > d ) {
            result = c;
        }
        else {
            result = d;
        }
    }
    else if ( b > c ) {
        if ( b > d ) {
            result = b;
        }
        else {
            result = d;
        }
    }
    else if ( c > d ) {
        result = c;
    }
    else {
        result = d;
    }

otherwise there are really better options in java, with supporting more count of numbers.

score 0 · Answer 2 · edited Oct 10 '20 at 10:21

0

int a = 545, b = 24, c = 75454, d = 68;
int result = 0;
if (a > b) {
    if (a > c && a > d) {
        result = a;
    } else {
        if (c > d) {
            result = c;
        } else {
            result = d;
        }
    }
} else {
    if (b > c && b > d) {
        result = b;
    } else {
        if (c > d) {
            result = c;
        } else {
            result = d;
        }
    }
}

System.out.println(result);

The code I made is super short and easy to implement

edited Oct 10 '20 at 10:21

David Buck

3,752
35
31
35

answered Oct 10 '20 at 10:15

Vyom Yadav

145
13

1

I missed the second part of your first question. Basically, the better your answer ( good content, well formatted so it's easy to read), the more likely it is to attract upvotes. The opposite is also true. If you haven't already, take a look at [answer] – David Buck Oct 10 '20 at 10:46

How to do nested if - else with 4 numbers to find biggest number

2 Answers2