Original answer:
Your std::vector, vec_ is const. Seems to me that would forcefully remove or disable any method, such as push_back(), which tries to modify the const vector.
Additions added 10 May 2020:
I think it's worth expounding upon this comment from @Carpetfizz in the comments under his question, too:
@GabrielStaples thanks, removing const did the trick. I thought const only protected against reassignment of vector_ but allowed for it to be mutated?
My response:
No, const here applies to the contents of the vector. The vector isn't a pointer, but what you're talking about could be done with pointers, by making the pointer itself const instead of the contents of what it points to const. Also, const and mutable are opposites. One undoes the other. You cannot have both in effect at the same time. By definition, something constant is immutable (unchangeable), and something mutable is non-constant.
And how might one make a pointer const but not the contents of what it points to?
First, consider the original code (with some minor modifications/fixes I did to it):
Run it yourself online here: https://onlinegdb.com/SyMqoeU9L
1) cpp_template_const_vector_of_smart_ptrs_test_BEFORE.cpp:
#include <iostream>
#include <memory>
#include <vector>
template <typename T>
class Container
{
private:
// const std::vector<std::shared_ptr<T>> vec_; // does NOT work
std::vector<std::shared_ptr<T>> vec_; // works!
public:
void append(std::shared_ptr<T> item)
{
vec_.push_back(std::move(item));
}
void printElements()
{
for (int i = 0; i < vec_.size(); i++)
{
// Don't forget to dereference the pointer with `*` in order to
// obtain the _contens of the pointer_ (ie: what it points to),
// rather than the pointer (address) itself
std::cout << *vec_[i] << std::endl;
}
}
};
int main(int argc, char** argv)
{
std::unique_ptr<Container<std::string>> c = std::make_unique<Container<std::string>>();
c->append(std::make_shared<std::string>("hello"));
c->append(std::make_shared<std::string>("world"));
c->printElements();
return 0;
}
Output:
hello
world
And here's the new code demonstrating how to make a constant pointer to a non-const vector. See my comments here, and study the changes:
Run it yourself online here: https://onlinegdb.com/HyjNx-L5U
2) cpp_template_const_vector_of_smart_ptrs_test_AFTER.cpp
#include <iostream>
#include <memory>
#include <vector>
template <typename T>
class Container
{
private:
// const std::vector<std::shared_ptr<T>> vec_; // does NOT work
// Create an alias to this type just to make the creation below less
// redundant in typing out the long type
using vec_type = std::vector<std::shared_ptr<T>>;
// NON-const object (vector)--so it can be changed
vec_type vec_;
// const pointer to NON-const object--so, vec_p_ can NOT be re-assigned to
// point to a new vector, because it is `const`! But, **what it points to**
// CAN be changed because it is NOT const!
vec_type * const vec_p_ = &vec_;
// This also does NOT work (in place of the line above) because it makes
// the **contents of what you're pointing to const**, which means again
// that the contents of the vector can NOT be modified.
// const vec_type * const vec_p_ = &vec_; // does NOT work
// Here's the compile-time error in gcc when compiling for C++17:
// main.cpp: In instantiation of ‘void Container<T>::append(std::shared_ptr<_Tp>) [with T = std::basic_string<char>]’:
// <span class="error_line" onclick="ide.gotoLine('main.cpp',78)">main.cpp:78:53</span>: required from here
// main.cpp:61:9: error: passing ‘const vec_type {aka const std::vector >, std::allocator > > >}’ as ‘this’ argument discards qualifiers [-fpermissive]
// vec_p_->push_back(std::move(item));
// ^~~~~~
// In file included from /usr/include/c++/7/vector:64:0,
// from main.cpp:22:
// /usr/include/c++/7/bits/stl_vector.h:953:7: note: in call to ‘void std::vector<_Tp, _Alloc>::push_back(std::vector<_Tp, _Alloc>::value_type&&) [with _Tp = std::shared_ptr >; _Alloc = std::allocator > >; std::vector<_Tp, _Alloc>::value_type = std::shared_ptr >]’
// push_back(value_type&& __x)
// ^~~~~~~~~
// To prove that vec_p_ can NOT be re-assigned to point to a new vector,
// watch this:
vec_type vec2_;
// vec_p_ = &vec2_; // COMPILE-TIME ERROR! Here is the error:
// main.cpp:44:5: error: ‘vec_p_’ does not name a type; did you mean ‘vec_type’?
// vec_p_ = &vec2_; // COMPILE-TIME ERROR!
// ^~~~~~
// vec_type
// BUT, this works just fine:
vec_type * vec_p2_ = &vec2_; // non-const pointer to non-const data
public:
void append(std::shared_ptr<T> item)
{
vec_p_->push_back(std::move(item));
}
void printElements()
{
for (int i = 0; i < vec_p_->size(); i++)
{
// Notice we have to use a double de-reference here now!
std::cout << *(*vec_p_)[i] << std::endl;
}
}
};
int main(int argc, char** argv)
{
std::unique_ptr<Container<std::string>> c = std::make_unique<Container<std::string>>();
c->append(std::make_shared<std::string>("hello"));
c->append(std::make_shared<std::string>("world"));
c->printElements();
return 0;
}
Output:
hello
world
