How do i reduce the number of outputs?

Question

Suppose I input n=5, how do i get the first 5 numbers as the output and not 10?

    #fibonacci sequence
n=int(input('Enter number of numbers: '))
a=1
b=0
for i in range(1,n+1):
    a=a+b
    b=a+b
    print(a)
    print(b)

Hi, can you add more details to your question? I'm not able to understand what kind of problem statement you're solving. — Harshit, May 08 '20 at 07:45
i am trying to make a programme for outputting the fibonacci sequence — Rachana, May 08 '20 at 08:44

score 1 · Answer 1 · answered May 08 '20 at 07:21

1

The way you are adding a and b in the for loop is wrong. If you use print twice it will print twice per loop.

n=int(input('Enter number of numbers: '))
a=1
b=0
for i in range(1,n+1):
    a, b = a + b, a
    print(a)

answered May 08 '20 at 07:21

Prudhvi

1,095
1
7
18

ErdoganOnal · Answer 2 · 2020-05-08T07:29:59.987

0

Try this out:

n = int(input('Enter number of numbers: '))
def fib(n):
    curr, next_ = 1, 1
    for _ in range(n):
        yield curr
        curr, next_ = next_, curr + next_
print(list(fib(n)))

edited May 08 '20 at 07:29

answered May 08 '20 at 07:21

ErdoganOnal

800
6
13

score 0 · Answer 3 · answered May 08 '20 at 07:21

n=int(input('Enter number of numbers: '))
a=1
b=0
for i in range(1,n+1):
    a, b = a + b, a
    print(a)

The problem with your approach is you go with step 2 each time. For example on one iteration you go from a=5, b=3 to a=13, b=8. So there is 2 * 5 outputs.

How do i reduce the number of outputs?

3 Answers3