C# specify only second optional argument and use the default value for first

Asked May 04 '20 at 16:11

Active May 04 '20 at 16:11

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I have a function defined like this:

public void Foo(string arg1="defaultvalueForArg1", string arg2="defaultvalueForArg2")
{
    ...
}

Now i want to call this function and provide a special value for arg2:

Foo("defaultvalueForArg1", "specialValueForArg2");

This works. But i must copy and paste and explicitly specify the value for arg1 and i think this is not very clean. For example if the default-value for arg1 changes I must search for every place where i probably want to update the value for arg1 to use the new default-value. Is there a syntax or option to use simply the default-value provided for arg1 specified in Foo? Something like Foo(_, "specialValueForArg2"); (using _ which you probably known as discards). I can probably overload Foo but my question is if there is a real "buildin-function" for this issue in C#.

asked May 04 '20 at 16:11

anion

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`Foo(arg2: "specialValueForArg2");` – Klaus Gütter May 04 '20 at 16:15
2

Does this answer your question? [Pass multiple optional parameters to a C# function](https://stackoverflow.com/questions/1996426/pass-multiple-optional-parameters-to-a-c-sharp-function) (specifically, look at the 2nd answer that links to an article about optional params) – devlin carnate May 04 '20 at 16:15
Have you considered named parameters here? – Pavel Anikhouski May 04 '20 at 16:15
@KlausGütter yes this is exactly what i need, thank you very much. – anion May 04 '20 at 16:26

C# specify only second optional argument and use the default value for first

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