Converting R if (seed) statement into Python

Question

Working on a project for my Stats class and I've hit a roadblock...

I need to convert this code, given by the professor...

# Set seed if required and determine if seed is not an integer  
#   
       if(!is.null(seed)) {   
              if(is.integer(seed)) set.seed(seed)   
              else stop("Non NULL or Integer Seed") 
       }

...into Python. I thought i got it right, but I'm coming up short with this expression.

 if seed != None :   
              if is_integer(seed) :
              rd.seed(seed)  
                  return
              else :
                  sys.exit("Non NULL or Integer Seed")

It gives me a "IndentationError: expected an indented block". Can you seed in Python without immediately following it with random.randint()?

Wow, that was super easy. You people are great, thank you!!! — Jack Karrde, May 04 '20 at 12:02
Wait, now it's giving me a "'TypeError: 'builtin_function_or_method' object is not subscriptable" — Jack Karrde, May 04 '20 at 12:19

score 1 · Answer 1 · answered May 04 '20 at 11:55

1

The indentation problem is at rd.seed(seed) line:

if seed != None:   
    if is_integer(seed):
      rd.seed(seed)  
      return
else:
  sys.exit("Non NULL or Integer Seed")

answered May 04 '20 at 11:55

Francesco Grossetti

1,555
9
17

Wait, now it's giving me a "'TypeError: 'builtin_function_or_method' object is not subscriptable" – Jack Karrde May 04 '20 at 12:19

score 0 · Answer 2 · answered May 04 '20 at 11:56

0

Be careful with the identations! Your code should be look like this:

if seed != None:   
    if is_integer(seed):
        rd.seed(seed)  
        return
else:
    sys.exit("Non NULL or Integer Seed")

answered May 04 '20 at 11:56

matebende

543
1
7
21

No need to add an answer if there is already one. Especially if they are the same. – Francesco Grossetti May 04 '20 at 12:00

Converting R if (seed) statement into Python

2 Answers2