I'm matching a string of a key value pair between characters "" with "(.*?)" how can I ignore any extra " characters within the value part.
example string {"1"=>"email@example.com"}
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stephen
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Could you please clarify *any extra " characters within the value part*? `"(.*?)"` finds all occurrences of substrings between double quotes. – Wiktor Stribiżew May 03 '20 at 18:58
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@WiktorStribiżew Example: {"1"=>"somest"ring" } For the value part I want to extract exactly as they entered it. result= somest"ring – stephen May 03 '20 at 19:07
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It is wrong, it should be `"somes\"tring"`. Please have it fixed on the provider's side. All workarounds are not nice. You might try `String pat = "(?<=\\{|=>)\"(.*?)\"(?=\\}|=>)"` but it might still fail in edge cases. See https://regex101.com/r/rduF7v/1 – Wiktor Stribiżew May 03 '20 at 19:10
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@WiktorStribiżew agreed it's broken - this will see me through. thank you. – stephen May 03 '20 at 19:19
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You may use
String pat = "(?<=\\{|=>)\"(.*?)\"(?=\\}|=>)";
See the regex demo
Details
(?<=\{|=>)- a positive lookbehind that matches a location immediately preceded with{or=>"- a double quotation mark(.*?)- Group 1: any zero or more chars other than line break chars, as few as possible"- a double quotation mark(?=\}|=>)- a positive lookahead that matches a location immediately followed with}or=>.
Wiktor Stribiżew
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