Checking Pangram in Python

Question

I am trying to use .pop to check the pangram and have the following code but get the error "'str' object has no attribute 'pop'". I am new to programming. Please help.

import string

def ispangram(str1, alphabet=string.ascii_lowercase):
    for x in str1:
        if x in alphabet:
            alphabet.pop[0]
        else:
            pass
    return len(alphabet)==0

`string.ascii_lowercase` is a string, not a list or dict, so it lacks the `pop` attribute — C.Nivs, May 03 '20 at 17:10
Following up @C.Nivs, also even if it was a list or dict, it would be a method, not an attribute. — iamvegan, May 03 '20 at 17:14
@iamvegan I think that borders on semantics, especially when calling a non-existent method raises an `AttributeError` — C.Nivs, May 04 '20 at 00:32

Sarangan · Answer 1 · 2020-05-03T17:23:26.950

List and dictionary objects only have popmethod.You are trying to delete the character in the 0th index of string. Thus you can try this :

def ispangram(str1, alphabet=string.ascii_lowercase):
    for x in str1:
        if x in alphabet:
            alphabet = alphabet[1:]
        else:
            pass
    return len(alphabet)==0

output

print (ispangram("The quick brown fox jump over the lazy dog", "s"))

False

score 0 · Answer 2 · answered May 03 '20 at 17:15

One approach is to use sets:

import string 

def check(s):
    """ 
    Return True if string s is Panagram
    """
    alphabet=string.ascii_lowercase
    return set(alphabet) - set(s.lower()) == set([])

PS: If you want to see what attributes/methods of an object just use dir(<object>)

Checking Pangram in Python

2 Answers2