How to Convert Hex "F08282AC" to char

Question

I am trying to convert hex string "F08282AC" to char using below code

Integer.parseInt(hex, 16)

but it throws

Exception in thread "main" java.lang.NumberFormatException: For input string: "F08282AC"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:583)

How can I convert it to char?

https://stackoverflow.com/questions/1599205/hex-to-int-number-format-exception-in-java — Peter S, Apr 29 '20 at 02:41

Peter S · Answer 1 · 2020-04-29T03:54:32.740

-1

1) Characters can only hold 16 bits.

The number you have would far exceed that. If you meant a character array, you could use the String.valueOf(Long.parseLong(hex, 16)).toCharArray()

In parts, we convert the number to base 10, then convert it to a string, then convert it to a character array of numbers.

edited Apr 29 '20 at 03:54

answered Apr 29 '20 at 02:42

Peter S

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The title says “to char” and the question mentions “to char” twice. – VGR Apr 29 '20 at 02:50
Ah you're right. I will edit my answer. – Peter S Apr 29 '20 at 02:53
*"Characters can only hold 8 bits"* A `char` is a 16-bit unsigned integer value, so that's wrong. This is Java, not Python. – Andreas Apr 29 '20 at 03:53
sorry, my apologies. @Andreas. This isn't a great question in the first place, because it doesn't make a lot of sense. – Peter S Apr 29 '20 at 03:54

How to Convert Hex "F08282AC" to char

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