How to get a file extension from path with any extension? Solved

Question

Solved! "../pictures/uploads/profile" I changed to "./pictures/uploads/profile". My mistake, sorry! And I used answer from @Kunal Raut

I want to get extension of file in PHP from path. I have this code:

$fileName = "../pictures/uploads/profile".$id.".*";
$ext = pathinfo($fileName, PATHINFO_EXTENSION);

$sourceImg = "../pictures/uploads/profile".$id.".".$ext."?".mt_rand();

I have folder with pictures. They can be in png or jpg or jpeg. And php file is in another folder. So how do that?

It will works for one file, not for a set of files. You are using .* like if you was getting all files with name "profile5.anything" — Curlas, Apr 28 '20 at 09:45
Does this answer your question? [PHP: How to search a file using wildcards](https://stackoverflow.com/questions/2562298/php-how-to-search-a-file-using-wildcards) — iainn, Apr 28 '20 at 09:55

Curlas · Answer 1 · 2020-04-28T10:04:40.730

0

$fileName = "../pictures/uploads/profile".$id.".*"; // <---- this is not a file,put a file name $ext = pathinfo($fileName, PATHINFO_EXTENSION);

Try this:

$files = scandir("../pictures/uploads/");
foreach ($files as $fileName) {
   $ext = pathinfo($fileName, PATHINFO_EXTENSION); 
}

edited Apr 28 '20 at 10:04

answered Apr 28 '20 at 09:47

Curlas

879
5
14

I have folder with pictures. They can be in png or jpg or jpeg. And php file is in another folder. So how do that? – UnexoN Apr 28 '20 at 09:50
You can read all the files in the folder. Ie: you can use scandir function. Ir returns an array with all files, then you can make a foreach. I have edit my answer. – Curlas Apr 28 '20 at 10:03
I edited my question. Maybe now it's easier to understand – UnexoN Apr 28 '20 at 10:04
@Curlas but it will return dots `.` in the first two array. – Kunal Raut Apr 28 '20 at 10:15
@Curlas But how $fileName must look then? 'cause id doesn't give extension – UnexoN Apr 28 '20 at 10:21

Marcel · Answer 2 · 2020-04-28T10:50:59.550

0

Just use the DirectoryIterator class.

foreach (new DirectoryIterator('../pictures/uploads') as $fileInfo) {
    if ($fileInfo->isDot()) continue;

    if (stripos($fileInfo->getFilename(), 'profile' . $id) !== false) {
        var_dump($fileInfo->getExtension());
    }
}

The DirectoryIterator class is available since PHP 5.3.6.

A more detailed example could be a DirectoryIterator instance used by a FilterIterator instance to just output the desired files. Th given example requires a minimum of PHP 7.4. If you 're using a PHP version smaller than 7.4 remove the type hints for the class properties.

class MyFileFilter extends FilterIterator
{
    protected string $filename;
    public function __construct(Iterator $iterator, $filename)
    {
        $this->filename = $filename;
        parent::__construct($iterator);
    }

    public function accept(): bool
    {
        $info = $this->getInnerIterator();
        return stripos($info->getFilename(), $this->filename) !== false;
    }
}

The FilterIterator class is available since PHP 5.1. The above shown extension takes an Iterator and searches for a given filename and returns the SplFileInfo object, if the filename matches.

How to use it:

$directory = new DirectoryIterator('../pictures/uploads');
$filename = 'picture' . $id;
$filter = new MyFileFilter($directory, $filename);

foreach ($filter as $file) {
    var_dump($file->getExtension());
}

The foreach loop is basically the filter, that only returns files, that match the given filename. Every returned file is a SplFileInfo instance. With this you can use the SplFileInfo::getExtension() method to get the file extension.

Last but not least comes the GlobIterator class which is available since PHP 5.3. It 's the easiest way to iteratate over a given path with placeholders.

$filesystem = new GlobIterator('../pictures/uploads/profile' . $id . '.*');
foreach ($filesystem as $file) {
    var_dump($file->getExtension());
}

edited Apr 28 '20 at 10:50

answered Apr 28 '20 at 09:50

Marcel

4,854
1
14
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I edited my question. Maybe now it's easier to understand – UnexoN Apr 28 '20 at 10:04
Well, if I understand your changes, you are searching for all files with a given filename in a specific path to get the file extension. That 's exactly what my given code examples do. – Marcel Apr 28 '20 at 10:05
"Parse error: syntax error, unexpected 'string' (T_STRING), expecting function (T_FUNCTION) or const (T_CONST)" on line with "protected string" – UnexoN Apr 28 '20 at 10:13
Well, that sounds like a PHP version < 7.4. What php version are you running? Try `echo PHP_VERSION;`. – Marcel Apr 28 '20 at 10:14
It's 7.2.30 version – UnexoN Apr 28 '20 at 10:19
I 've edited my answer and gave you an example for the GlobIterator class, which is available since PHP 5.3. This should work. – Marcel Apr 28 '20 at 10:21
Still don't get extension – UnexoN Apr 28 '20 at 10:24
What do you get instead? What did you try from the above? Are you using the right directory? Does a filename with the given `$id` even exist in the directory? Show me some code. – Marcel Apr 28 '20 at 10:27
Well ... you should not just copy code from stack overflow! Try to understand, what the code does and transfer that to your application. The line `$ext = var_dump($file->getExtension);` can not work! Change it into `$ext = $file->getExtension();`. – Marcel Apr 28 '20 at 10:33
I changed that but still can't got extension – UnexoN Apr 28 '20 at 10:36
Solved! "../pictures/uploads/profile" I changed to "./pictures/uploads/profile". My mistake, sorry! And I used answer from @Kunal Raut – UnexoN Apr 28 '20 at 12:06

Kunal Raut · Accepted Answer · 2020-04-28T10:58:54.810

-1

You can get all the extensions in the directory by using the function scandir() as

$fileName = scandir("../pictures/uploads/");
$ext = "";
foreach($fileName as $files) {
if($files !== '.' && $files !== '..') {
$ext = pathinfo($files, PATHINFO_EXTENSION);
 }
}
 echo $ext .'<br>';

Usually scandir() returns the first two values in the array as . and .. and by if condition mentioned in the answer you can delete these unwanted values and get the answer in the pure form.

Note : scandir() returns the values in the form of array.

i got it working see below

edited Apr 28 '20 at 10:58

answered Apr 28 '20 at 10:36

Kunal Raut

2,495
2
9
25

i have posted a working example image for you check it out and also do check my edited code. – Kunal Raut Apr 28 '20 at 10:56

How to get a file extension from path with any extension? Solved

3 Answers3