Why am I getting a TypeError in my function?

Question

I wrote this function to "score" hands for a Python blackjack game (I know aces can be 1 or 11, that's a future problem to figure out). The input is a list of tuples (cards), and the rank can be either 2-10 or A, J, K, or Q.

I'm sometimes getting a TypeError that reads TypeError: unsupported operand type(s) for +: 'int' and 'str' in reference to score = score + rank. I'm not sure why there's an issue though, because if it gets to that point the rank must be an int. Anyone see the issue?

def analyzeHand(hand):
    score = 0
    for card in hand:
        rank = card[0]
        if (rank == 'A'):
            score = score + 11
        if (rank == 'K' or rank == 'Q' or rank == 'J'):
            score = score + 10
        else:
            score = score + rank
    return score

You should debug your code. Print `rank` before adding it to score. It may not be an integer. — Jan, Apr 24 '20 at 19:02
Your second `if` should be `elif`. Otherwise, if `rank` is `'A'`, the `else` block will be executed. — Thierry Lathuille, Apr 24 '20 at 19:04

score 1 · Answer 1 · edited Apr 24 '20 at 19:06

1

That score = score + rank in the last else should likely be

score += int(rank)

because from context rank is of type str, assumed to be "2".."9".

edited Apr 24 '20 at 19:06

user2864740

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answered Apr 24 '20 at 19:02

Cory Kramer

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Nit: It *is* a string per the error, the assumption is then only on the value(s). – user2864740 Apr 24 '20 at 19:06

Why am I getting a TypeError in my function?

1 Answers1