Printing a double pointer to a linked list in C

Asked Apr 24 '20 at 15:46

Active Jun 14 '21 at 21:07

Viewed 35 times

A linked list defined as:

typedef struct linkedList_struct {
    short unsigned int num;
    struct linkedList_struct *next ;
} linkedList;

I'm trying to print out the num value of **head when **head is passed to the function

int function(linkedList **head) 
{
   printf("%X\n, head->num);  // I get error here: error: member reference base type 'linkedList*' (aka 'struct linkedList_struct *') is not a structure or union
}

How do I dereference this double pointer to a linked list node so that I can print out head->num value?

edited Jun 14 '21 at 21:07

halfer

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asked Apr 24 '20 at 15:46

Katie Melosto

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`linkedList**` is a *pointer-to-a-pointer-of-linkedList*, so `(*head)->num` should work. – Ruks Apr 24 '20 at 15:48
@Ruks Thank you - that did it – Katie Melosto Apr 24 '20 at 15:51

Printing a double pointer to a linked list in C

0 Answers0