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hi I trying to get a request to https://www.playerup.com/ with blow code :

import requests
header = {"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.163 Safari/537.36"}
r = requests.get("https://www.playerup.com/",headers=header)
print(r.status_code)

but it give me a [503]type error I trying timeout for 5 second and also not work how I should fix it ?

atropates
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1 Answers1

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So times using a referer and google cache can help you avoid these failures. So your code should be:

# here added a referer
header = {"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36" ,'referer':'https://www.google.com/'}
# now use a google cache
r = requests.get("http://webcache.googleusercontent.com/search?q=cache:www.playerup.com/",headers=header)

Now see the status code:

>>>r
<Response [200]>
Joshua Varghese
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