functional way of creating defaultdict[list]?

Asked Apr 20 '20 at 12:08

Active Apr 20 '20 at 12:08

Viewed 18 times

Basically I've found this and similar code a bunch of times now:

items_by_parent = defaultdict(list)
for item in items:
    items_by_parent[item.parent].append(item)

I come from a C# background and was a heavy linq user where you'd go list.GroupBy(...).ToDictionary(...), so this snippet grinds my gears to some extent. Which leads me to ask: Is there some functional way to achieve the same result in python?

Thanks :)

asked Apr 20 '20 at 12:08

FrankyBoy

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The only thing similar to this would be using Pandas API, and it would look something like this - https://stackoverflow.com/a/29876239/1737811 – mutantkeyboard Apr 20 '20 at 12:14
What kind of object is an `item`? – Roland Smith Apr 20 '20 at 12:16
If you had a list of possible `parent`s you could use a dict-comprehension, but the code above is definitely more efficient – Tomerikoo Apr 20 '20 at 12:18

functional way of creating defaultdict[list]?

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