How do I run a firebase function locally in one line in the cmd?

Question

My operating system is windows 10.
I have a scheduled firebase function that I would like to run locally:

functions = require('firebase-functions')
admin = require('firebase-admin')
exports.myFunction = functions.pubsub.schedule('every 30 minutes').onRun((context) => {
    console.log('Hello World!')
    return null
})

To run this function locally I run two commands(Answer taken from here):

firebase functions:shell
myFunction()

Can I execute this command in one line of code instead of two?

What is your host operating system? – Doug Stevenson Apr 16 '20 at 23:27 — Doug Stevenson, Apr 16 '20 at 23:27
My host operating system is Windows 10 – yuval Apr 16 '20 at 23:33 — yuval, Apr 16 '20 at 23:33

score 0 · Answer 1 · answered Jan 01 '21 at 18:54

Separate out the function logic from the scheduling logic, then call the function directly with node:

function.js:

const functions = require('firebase-functions')
const admin = require('firebase-admin')
const foo = require('./foo')
exports.myFunction = functions.pubsub.schedule('every 30 minutes').onRun(foo)

foo.js:

module.exports = (context) => {
  console.log('Hello World!')
  return null
}

Call with node in one line:

node -e 'require("./foo")()'

Note: You may need to manually supply the configuration/credentials in foo.js depending on what Firebase resources you are accessing since you are not running it in a Cloud environment when you call it directly.

How do I run a firebase function locally in one line in the cmd?

1 Answers1