How to work around problem with Python smtpd?

Question

I want to make a small SMTP server for testing, using Python, so I was trying the server example code

import smtpd
import asyncore

class CustomSMTPServer(smtpd.SMTPServer):

def process_message(self, peer, mailfrom, rcpttos, data):
    print 'Receiving message from:', peer
    print 'Message addressed from:', mailfrom
    print 'Message addressed to  :', rcpttos
    print 'Message length        :', len(data)
    return

server = CustomSMTPServer(('127.0.0.1', 1025), None)

asyncore.loop()

Together with the example client code on that same page:

import smtplib
import email.utils
from email.mime.text import MIMEText

# Create the message
msg = MIMEText('This is the body of the message.')
msg['To'] = email.utils.formataddr(('Recipient', 'recipient@example.com'))
msg['From'] = email.utils.formataddr(('Author', 'author@example.com'))
msg['Subject'] = 'Simple test message'

server = smtplib.SMTP('127.0.0.1', 1025)
server.set_debuglevel(True) # show communication with the server
try:
    server.sendmail('author@example.com', ['recipient@example.com'], msg.as_string())
finally:
    server.quit()

However, when I try to run the client, I am getting the following on the server side:

error: uncaptured python exception, closing channel <smtpd.SMTPChannel connected 127.0.0.1:38634 at 0x7fe28a901490> (<class 'TypeError'>:process_message() got an unexpected keyword argument 'mail_options' [/root/Python-3.8.1/Lib/asyncore.py|read|83] [/root/Python-3.8.1/Lib/asyncore.py|handle_read_event|420] [/root/Python-3.8.1/Lib/asynchat.py|handle_read|171] [/root/Python-3.8.1/Lib/smtpd.py|found_terminator|386])
^CTraceback (most recent call last):
  File "./mysmtpd.py", line 18, in <module>
asyncore.loop()
  File "/root/Python-3.8.1/Lib/asyncore.py", line 203, in loop
poll_fun(timeout, map)
  File "/root/Python-3.8.1/Lib/asyncore.py", line 144, in poll
r, w, e = select.select(r, w, e, timeout)
KeyboardInterrupt

Then I found this Issue page:

https://bugs.python.org/issue35837

and I think that that is the problem I've been running into.

That issue hasn't been fixed yet, so I was wondering if, meantime, is there something that I can modify in the example client code that would get around the problem that is described in that issue?

Thanks, Jim

score 0 · Answer 1 · edited Aug 07 '20 at 06:23

0

Add an mail_options=None in your process_message() function.

edited Aug 07 '20 at 06:23

סטנלי גרונן

2,917
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answered Aug 07 '20 at 05:44

steve

1

how so? I'm having the same issue. – Zach Oakes Apr 09 '21 at 23:46

score -1 · Answer 2 · answered Jun 07 '21 at 19:58

-1

Just for reference, do the same with the rcpt_options argument.

Ref: https://docs.python.org/3/library/smtpd.html?highlight=process_message#smtpd.SMTPServer.process_message

answered Jun 07 '21 at 19:58

user16042504

31
4

Consider adding this as a comment or add here some details from that link. – nobleknight Jun 08 '21 at 06:45

score -1 · Answer 3 · edited Jan 18 '22 at 13:43

-1

The error seems to appear in the line with def process_message(self, peer, mailfrom, rcpttos, data):. You can replace it with def process_message(self, peer, mailfrom, rcpttos, data,**my_krargs):

edited Jan 18 '22 at 13:43

radrow

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answered Jan 16 '22 at 11:03

wogob

1
1

How to work around problem with Python smtpd?

3 Answers3