Creating a list that never repeats random number

Asked Apr 08 '20 at 21:46

Active Apr 08 '20 at 21:46

Viewed 31 times

I have my program functioning properly, but, I want the answer list to never have a duplicated number, and also always have 4 numbers. I have tried using the function

num_digits = 4

answer = []
for i in range(num_digits):
    r = random.randint(0,9)
    if r not in answer: answer.append(r)

but this returns three or even two numbers sometimes. I need 4 numbers in the list each time. My current code looks like this

def game(number_of_digits):
    answer = [random.randint(0,9) for n in range(number_of_digits)]

Thank you!

asked Apr 08 '20 at 21:46

Gavin

1

How about your for loop iterating until the length of answer is `num_digits’? – DisappointedByUnaccountableMod Apr 08 '20 at 21:49
6

What about `random.sample(range(0,9), 4)` – JvdV Apr 08 '20 at 21:49
Either of the above, though @barry probably should have said a while loop not for, that is while (answer length < 4) – Dave S Apr 08 '20 at 21:50
I like both ideas. I think I will keep the for loop for now. Try the random.sample – Gavin Apr 08 '20 at 21:54
1

Thanks a lot. JvdV worked like a charm. Really appreciate it! – Gavin Apr 08 '20 at 21:57

Creating a list that never repeats random number

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