Enumerate returning multiple indexes as integer from list

Question

I am trying to get indexes for adams and lewis from a list.

Presidents = ['washington','adams','jeff','lewis']

def index():
    for index,name in enumerate(Presidents):
        if name == 'adams':
            return index

print(index())

How can I modify this function? So that when the function index() is called, it should return the index of adams and lewis as integers.

You can do `Presidents.index('adams')`, `Presidents.index('lewis')`. If you like'd to get indices as a list, you can use `[Presidents.index(name) for name in ['adams', 'lewis']]` — CodeIt, Apr 08 '20 at 14:50
Does this answer your question? [Finding the index of an item in a list](https://stackoverflow.com/questions/176918/finding-the-index-of-an-item-in-a-list) — CodeIt, Apr 08 '20 at 14:55

score -1 · Answer 1 · answered Apr 08 '20 at 14:54

You can just reuse the index method.

The method returns the index of the element in the list.

If not found, it raises a ValueError exception indicating the element is not in the list.

def index(name):
  return Presidents.index(name)


print(index('adams'))
print(index('lewis'))

Enumerate returning multiple indexes as integer from list

1 Answers1