1

A declaration and definition mismatch in my template class (everything irrelevant has been cut out):

template <typename LanguageMap>
class WidgetLanguageManager
{
    public:
        enum class Language { DE, ENG, PL };
    protected:
        Language language;
        //Some protected fields
    public:
        explicit WidgetLanguageManager(const Language& language);
        explicit WidgetLanguageManager(const QString& language);
        Language ToLanguage(const QString& language);
    protected:
        //some protected methods
};


template <typename LanguageMap>
Language WidgetLanguageManager<LanguageMap>::ToLanguage(const QString& language) // this cannot be matched with a declaration
{
    for (QChar& c: language)
    {
        c = c.toLower();
    }

    switch (language)
    {
        case "german": return Language::DE;
        case "english": return Language::ENG;
        case "polish": return Language::PL;
    }
    throw RuntimeError("Wrong language paremeter.");
}

Please help because I cannot see any reason behind that.

NutCracker
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slavic-d
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2 Answers2

2

Following would work:

template <typename LanguageMap>
typename WidgetLanguageManager<LanguageMap>::Language WidgetLanguageManager<LanguageMap>::ToLanguage(const QString& language)
// ^^^^^ 'typename' keyword needed because 'Language' is dependent name

Since enum class Language is part of WidgetLanguageManager template class, you need to precede it with the scope operator.

NutCracker
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    This helped: template typename WidgetLanguageManager::Language WidgetLanguageManager::ToLanguage(const QString& language) – slavic-d Apr 07 '20 at 07:24
1

Alternatively to extra typename, you might use trailing return type:

template <typename LanguageMap>
auto WidgetLanguageManager<LanguageMap>::ToLanguage(const QString& language)
-> Language
{
/*..*/
}
Jarod42
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