How to fix TypeError: 'str' object cannot be interpreted as an integer

Question

here's my code

import string
import random
len1 = input("Enter the length of the password you need\n")
ch1 = input("Enter the type\nUpper + Lower ---> 1\nAll Combined ---> 2\n")
if ch1 == '1':
chars = string.ascii_letters
x = ''.join(random.choice(chars) for i in range(len1))
print("Generated Password Based Upon Your Request Is '{0}'".format(x))
elif ch1 == '2':
for i in range(5):
    chars = string.ascii_uppercase + string.ascii_lowercase
    ide = chars + string.digits
    y = ''.join(random.choice(ide) for i in range(len1))
    print("The Generated Password Based Upon Your Request Is '{0}'".format(y))
    print("-----------------")
    print("If Not Generated, You Can Repeat the Process Again Upto {0} times".format(4-i))
    print("-----------------")
    rec = input("Want 2 Repeat?? Press 1; Else 2\n")
    if rec == 1:
        continue
    else:
        break

I am getting x = ''.join(random.choice(chars) for i in range(len1)) TypeError: 'str' object cannot be interpreted as an integer. Pls fix my code and tell me the error.

Also, use `random.choices(ide, k=int(len1))` rather than calling `random.choice` multiple times. — chepner, Apr 01 '20 at 14:18

A. Abramov · Accepted Answer · 2020-04-01T14:22:44.987

1

The result of the input(...) function, is a string - and so your len1 param is a string. To use it in a range function, convert it to an integer. Edit: As chepner mentioned, that will only work if len1 is an int. You can check that - one way to do this is described here:

try:
   x = ''.join(random.choice(chars) for i in range(int(len1)))
except ValueError:
   print('len1 isnt an integer')

edited Apr 01 '20 at 14:22

answered Apr 01 '20 at 14:13

A. Abramov

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Yeah, it's working. Thanks bro – Srikar Kailash Apr 01 '20 at 14:40
but, len1 is an integer, right? How can you say it is a string?? – Srikar Kailash Apr 01 '20 at 14:44
It might be not convertible, e.g "one" – A. Abramov Apr 01 '20 at 14:53

Hamza Lachi · Answer 2 · 2020-04-01T14:23:36.260

0

Why You Are Getting This Error?

Because If You Pass A Data in input it will be string and the range function take int object so you need to convert string to integer

There Are 2 Ways You Can Try

Way1:

x = ''.join(random.choice(chars) for i in range(int(len1)))

Way2 Recommended:

while True:
    try:
        len1 = int(input("Enter the length of the password you need\n"))
        break
    except ValueError:
        print('Please Add Integer Value!')

edited Apr 01 '20 at 14:23

answered Apr 01 '20 at 14:17

Hamza Lachi

1,046
7
25

Neither one addresses the possibility of `int` raising a `ValueError` on a bad input. – chepner Apr 01 '20 at 14:19
@chepner Sorry I Forget To Add Len1 Input – Hamza Lachi Apr 01 '20 at 14:21
Hazma that's not what he's saying. He's saying len1 could be a string thats not easily converted to an int, e.g "one". – A. Abramov Apr 01 '20 at 14:23
It's Working. Thanks!! – Srikar Kailash Apr 01 '20 at 14:44

How to fix TypeError: 'str' object cannot be interpreted as an integer

2 Answers2