Is there an equivalent of Array#each_slice() in Ruby 1.8.5?

Question

I'm using ruby 1.8.5, and the each_slice() method for an array is not working.

My code is something like:

array.each_slice(3) do |name,age,sex|   .....   end

Is there any other way to implement the same functionality in my older version of ruby.

@the Tin Man: What was wrong with the ruby-1.8 tag? – Andrew Grimm May 24 '11 at 00:08 — Andrew Grimm, May 24 '11 at 00:08

steenslag · Accepted Answer · 2011-05-28T23:49:13.127

5

Bake your own:

module Enumerable
  def each_slice( n )
    res = []
    self.each do |el|
      res << el
      if res.size == n then
        yield res.dup
        res.clear
      end
    end
    yield res.dup unless res.empty?
  end
end

edited May 28 '11 at 23:49

answered May 23 '11 at 10:39

steenslag

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score 1 · Answer 2 · edited May 28 '11 at 14:30

1

This guy

http://tekhne.wordpress.com/2008/02/01/whence-arrayeach_slice/

figured out you can

require 'enumerator'

and it works

edited May 28 '11 at 14:30

Andrew Grimm

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answered May 28 '11 at 06:29

buck

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score 0 · Answer 3 · answered May 23 '11 at 10:10

0

I haven't got 1.8.5, but you can try this

0.step(array.size, 3) do |i|
  name, age, sex = array[i], array[i+1], array[i+2]
  ...
end

answered May 23 '11 at 10:10

fl00r

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thank u very much for ur reply.. In The above code, say for eg if the no. of elements is 3, it works fine for one iteration but in the second and third iteration, the name,age,sex returns nil... – sundar May 23 '11 at 10:26

score 0 · Answer 4 · answered May 23 '11 at 23:17

0

I haven't used it myself, but consider using the backports gem.

answered May 23 '11 at 23:17

Andrew Grimm

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Is there an equivalent of Array#each_slice() in Ruby 1.8.5?

4 Answers4