Sendgrid Python reply_to email

Question

I have errors when I use reply_to, here is what I've tried...

This works but without reply_to :

mail = Mail(
    from_email = from_email,
    to_emails = to_email,
    subject = subject,
    html_content = content)
response = sg.client.mail.send.post(request_body=mail.get())

And I've tried this :

mail = Mail(
    reply_to = reply,
    from_email = from_email,
    to_emails = to_email,
    subject = subject,
    html_content = content)
response = sg.client.mail.send.post(request_body=mail.get())

This thows :

TypeError: init() got an unexpected keyword argument 'reply_to'

I have also tried to add this after Mail() :

mail.from_EmailMessage(reply_to=ReplyTo(Email(email=ANS_EMAIL,name='Mr X')))

Which throws :

TypeError: object of type 'Email' has no len()

And :

mail.reply_to(ReplyTo(email=ANS_EMAIL,name='Mr X'))

Which throws :

TypeError: 'NoneType' object is not callable

Any help please ?

Issue is you're using mail.reply_to like a function but it's a setter so use it like a property (as mentioned in answer below) ie mail.reply_to = xxx vs mail.reply_to(xxx) — hurlbz, Apr 23 '21 at 16:10

Subhrajyoti Das · Answer 1 · 2020-06-04T10:54:07.147

4

As your error states reply_to is not accepted in init(). Try setting reply_to after you have created the Mail object.

Example Below:

mail.reply_to = "reply-to@website.com"

or 

message.reply_to = ReplyTo('reply-to@website.com', 'Reply Here')

More details on how to customize sendgrid email object - Link

edited Jun 04 '20 at 10:54

answered Jun 04 '20 at 09:22

Subhrajyoti Das

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1

mail.reply_to = "reply-to@website.com" worked for me! – Sharpless512 Aug 25 '20 at 08:21

score 2 · Answer 2 · answered Jun 26 '20 at 12:48

I managed doing this :

data = {
    "personalizations": [
     {
      "send_at": date,
      "subject": objet,
      "to": [{"email": to_email}],
     }
 ],
 "from": {"email": FROM_EMAIL, "name": "..."},
 "reply_to": {"email": "...@...", "name": "..."},
 "send_at": date,
 "subject": objet,
 "content": [
     {
      "type": "text/html",
      "value": body
     }
  ]
}
response = sg.client.mail.send.post(request_body=data)

Sendgrid Python reply_to email

2 Answers2