AWK - Reverse field order

Question

How can I print the second Field, counting from the end of the fields, dynamically?

input

4 6 5 6 4

4 5 6

7 8 9 6 3

4 5 6

I would like to print the second column, numbered from the last record (dynamically)

The desired result is:

I tried -$2 that does not work.

See: [Print second last column/field in awk](https://stackoverflow.com/q/2096490/3776858) — Cyrus, Mar 28 '20 at 15:34
Does this answer your question? [Print second last column/field in awk](https://stackoverflow.com/questions/2096490/print-second-last-column-field-in-awk) — Daemon Painter, Mar 28 '20 at 19:01

RavinderSingh13 · Accepted Answer · 2020-03-28T13:40:41.147

2

Could you please try following, written and tested with shown samples.

awk '{print $(NF-1)}' Input_file

Where NF is out of the box(default) variable of awk and represents the total number of fields in a line. So what I have done is after $ I have put NF-1 means telling to print 2nd last field here.

edited Mar 28 '20 at 13:40

answered Mar 28 '20 at 13:33

RavinderSingh13

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AWK - Reverse field order

1 Answers1