Filter data from object inside another object

Question

I have a situation like this:

var first = [
    {'id': 1},
    {'id': 2},
    {'id': 3},
    {'id': 4}
];
var second = [
    {'id': 2},
    {'id': 4}
];

I would like to filter all elements from "first" where the id is inside "second". I am trying something like this:

var result = first.filter((x:any) => second.id.indexOf(x.id) < 0);

I tried with foreach, but it did not work. The result I would like to get is this:

var first = [
    {'id': 2},
    {'id': 4}
];

score 1 · Answer 1 · answered Mar 24 '20 at 17:49

1

You can use .filter() and .some() combination.

Try the following:

const first = [
    {'id': 1},
    {'id': 2},
    {'id': 3},
    {'id': 4}
];

const second = [
    {'id': 2},
    {'id': 4}
];

const result1 = first.filter(e => second.some(s => s.id === e.id));
console.log('includes', result1);

const result2 = first.filter(e => !second.some(s => s.id === e.id));
console.log('not includes', result2);

I hope this helps!

answered Mar 24 '20 at 17:49

norbitrial

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1

Thank you! That is exactly what i wanted! – Andre Naves Mar 24 '20 at 17:55
1

@AndreNaves Great, happy to help! Feel free to accept as the answer or upvote if it solves your problem. Appreciate. – norbitrial Mar 24 '20 at 18:00

Filter data from object inside another object

1 Answers1