Cannot store a long type variable in a HashMap in Java

Question

So I tried to store a big integer number in a HashMap like below:

    import java.util.*;
    public class MyClass {

        public static void main(String[] args) {
            HashMap<String, Long> phonebook = new HashMap<String, Long>();
            phonebook.put("John", 85972252904);
            Integer a = phonebook.get("John");
            System.out.println(a);
        }
    }

The code didn't work. Eclipse told me that "the literal 85972252904 of type int is out of range". So I wanna ask:

1) What is my problem here? 2) Furthermore, HashMap only accepts Classes as its parameters, and I just found out that the class "Long" is deprecated. What am I supposed to use to store a big integer as an object now?

Thanks for reading.

The range error is nothing to do with the map. If you try and use the literal `85972252904` anywhere you would get a similar error. — khelwood, Mar 24 '20 at 15:54
Phone number isn't actually quite a number. It's close, but you're still better off using some other way of storing it. — M. Prokhorov, Mar 24 '20 at 16:08
Class `Long` is not deprecated, where did you get that idea? — greg-449, Mar 24 '20 at 16:29

score 0 · Answer 1 · answered Mar 24 '20 at 15:55

0

Add an 'L' to the literal so it's treated as a long: 85972252904L

answered Mar 24 '20 at 15:55

TrogDor

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also problem here `Integer a = phonebook.get("John");` – Youcef LAIDANI Mar 24 '20 at 15:56
Agreed, that will get a class cast exception – TrogDor Mar 24 '20 at 15:58
thanks, it worked. The Integer part is when I tried to change it to an int to see if it still works, and then forgot to change it back before posting. – Thang Nguyen Mar 24 '20 at 16:02

Cannot store a long type variable in a HashMap in Java

1 Answers1