max in a list of tuples (Python)

Question

I have this list of list of tuples

var1 = [
    [(10, '♣'), (7, '♠')],
    [(14, '♣'), (2, '♣')],
    [(2, '♥'), (9, '♦')],
    [(11, '♠'), (10, '♠')],
    [(11, '♦'), (5, '♣')]
]

and I wanna extract the tuple with the maximun value which is the second one or var1[1]. I've used a lot of different codes during my programming but the one I'm using now and until now and didn't have any major issues is this one:

 maximo = max(var1, key=lambda x: sum(i for i,_ in x))

also this one:

 maximo2 = list(map(max,zip(*var1)))

The problem is I need the list with the biggest value, not the one with the combinations of the 2 biggest, and right now this code is outputting var1[3] as the bigger of the 2 and I don't know what else to try.

score 5 · Accepted Answer · answered Mar 19 '20 at 10:16

Use max instead of sum

Ex:

var1=[[(10, '♣'), (7, '♠')], [(14, '♣'), (2, '♣')], [(2, '♥'), (9, '♦')], [(11, '♠'), (10, '♠')], [(11, '♦'), (5, '♣')]]
maximo=max(var1, key=lambda x: max(i for i,_ in x))
print(maximo)

Output:

[(14, '♣'), (2, '♣')]

kederrac · Answer 2 · 2020-03-19T10:42:41.337

1

you can use the built-in function max with parameter key:

max(var1, key=max)

output:

[(14, '♣'), (2, '♣')]

edited Mar 19 '20 at 10:42

answered Mar 19 '20 at 10:23

kederrac

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score 0 · Answer 3 · answered Mar 19 '20 at 10:29

You could use max and operator.itemgetter here as well:

>>> from operator import itemgetter
>>> var1=[[(10, '♣'), (7, '♠')], [(14, '♣'), (2, '♣')], [(2, '♥'), (9, '♦')], [(11, '♠'), (10, '♠')], [(11, '♦'), (5, '♣')]]
>>> max(var1, key=itemgetter(0))
[(14, '♣'), (2, '♣')]

max in a list of tuples (Python)

3 Answers3