4

There is a list of conversations and every conversation has a list of messages. Every message has different fields and an action field. We need to consider that in the first messages of the conversation there is used the action A, after a few messages there is used action A.1 and after a while A.1.1 and so on (there is a list of chatbot intents).

Grouping the messages actions of a conversation will be something like: A > A > A > A.1 > A > A.1 > A.1.1 ...

Problem:

I need to create a report using ElasticSearch that will return the actions group of every conversation; next, I need to group the similar actions groups adding a count; in the end will result in a Map<actionsGroup, count> as 'A > A.1 > A > A.1 > A.1.1', 3.

Constructing the actions group I need to eliminate every group of duplicates; Instead of A > A > A > A.1 > A > A.1 > A.1.1 I need to have A > A.1 > A > A.1 > A.1.1.

Steps I started to do:

{
   "collapse":{
      "field":"context.conversationId",
      "inner_hits":{
         "name":"logs",
         "size": 10000,
         "sort":[
            {
               "@timestamp":"asc"
            }
         ]
      }
   },
   "aggs":{
   },
}

What I need next:

  1. I need to map the result of the collapse in a single result like A > A.1 > A > A.1 > A.1.1. I've seen that in the case or aggr is possible to use scripts over the result and there is possible to create a list of actions like I need to have, but aggr is doing the operations over all messages, not only over the grouped messages that I have in collapse. It is there possible to use aggr inside collapse or a similar solution?
  2. I need to group the resulted values(A > A.1 > A > A.1 > A.1.1) from all collapses, adding a count and resulting in the Map<actionsGroup, count>.

Or:

  1. Group the conversations messages by conversationId field using aggr (I don't know how can I do this)
  2. Use script to iterate all values and create the actions group for every conversation. (not sure if this is possible)
  3. Use another aggr over all values and group the duplicates, returning Map<actionsGroup, count>.

Mappings:

"mappings":{
  "properties":{
     "@timestamp":{
        "type":"date",
        "format": "epoch_millis"
     }
     "context":{
        "properties":{
           "action":{
              "type":"keyword"
           },
           "conversationId":{
              "type":"keyword"
           }
        }
     }
  }
}

Sample documents of the conversations:

Conversation 1.
{
    "@timestamp": 1579632745000,
    "context": {
        "action": "A",
        "conversationId": "conv_id1",
    }
},
{
    "@timestamp": 1579632745001,
    "context": {
        "action": "A.1",
        "conversationId": "conv_id1",
    }
},
{
    "@timestamp": 1579632745002,
    "context": {
        "action": "A.1.1",
        "conversationId": "conv_id1",
    }
}

Conversation 2.
{
    "@timestamp": 1579632745000,
    "context": {
        "action": "A",
        "conversationId": "conv_id2",
    }
},
{
    "@timestamp": 1579632745001,
    "context": {
        "action": "A.1",
        "conversationId": "conv_id2",
    }
},
{
    "@timestamp": 1579632745002,
    "context": {
        "action": "A.1.1",
        "conversationId": "conv_id2",
    }
}

Conversation 3.
{
    "@timestamp": 1579632745000,
    "context": {
        "action": "B",
        "conversationId": "conv_id3",
    }
},
{
    "@timestamp": 1579632745001,
    "context": {
        "action": "B.1",
        "conversationId": "conv_id3",
    }
}

Expected result:

{
    "A -> A.1 -> A.1.1": 2,
    "B -> B.1": 1
}
Something similar, having this or any other format.
Daniel Widdis
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Radu Linu
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    You can use terms aggregation to group on a key. If you can add mapping, sample document and expected result, it will be easier to understand the problem – jaspreet chahal Mar 12 '20 at 09:18
  • @jaspreetchahal I added some extra details. – Radu Linu Mar 12 '20 at 09:34
  • Do you need count of conversationId ex convs1->2, convs2->1 ? What is the role of action group here? – jaspreet chahal Mar 12 '20 at 09:59
  • No. I need the count of conversations `actions group`. Like every conversation has a list of actions `A -> A.1 -> A.1.1`, this is the `actions group`; I need to know the count of the `actions group`. – Radu Linu Mar 12 '20 at 10:06
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    I would suggest you ditch the aggregation and write a full script yourself. https://www.elastic.co/guide/en/elasticsearch/reference/master/modules-scripting-painless.html – Alexander Mikhalchenko Mar 15 '20 at 01:22
  • Thanks, a lot! This was the way I resolved my problem. – Radu Linu Mar 17 '20 at 10:48

2 Answers2

1

I solved it using the scripted_metric of elastic. Also, the index was changed from the initial state.

The script:

{
   "size": 0,
   "aggs": {
        "intentPathsCountAgg": {
            "scripted_metric": {
                "init_script": "state.messagesList = new ArrayList();",
                "map_script": "long currentMessageTime = doc['messageReceivedEvent.context.timestamp'].value.millis; Map currentMessage = ['conversationId': doc['messageReceivedEvent.context.conversationId.keyword'], 'time': currentMessageTime, 'intentsPath': doc['brainQueryRequestEvent.brainQueryRequest.user_data.intentsHistoryPath.keyword'].value]; state.messagesList.add(currentMessage);",  
                "combine_script": "return state",
                "reduce_script": "List messages = new ArrayList(); Map conversationsMap = new HashMap(); Map intentsMap = new HashMap(); String[] ifElseWorkaround = new String[1]; for (state in states) { messages.addAll(state.messagesList);} messages.stream().forEach((message) -> { Map existingMessage = conversationsMap.get(message.conversationId); if(existingMessage == null || message.time > existingMessage.time) { conversationsMap.put(message.conversationId, ['time': message.time, 'intentsPath': message.intentsPath]); } else { ifElseWorkaround[0] = ''; } }); conversationsMap.entrySet().forEach(conversation -> { if (intentsMap.containsKey(conversation.getValue().intentsPath)) { long intentsCount = intentsMap.get(conversation.getValue().intentsPath) + 1; intentsMap.put(conversation.getValue().intentsPath, intentsCount); } else {intentsMap.put(conversation.getValue().intentsPath, 1L);} }); return intentsMap.entrySet().stream().map(intentPath -> [intentPath.getKey().toString(): intentPath.getValue()]).collect(Collectors.toSet()) "
            }
        }
    }
}

Formatted script (for better readability - using .ts):

scripted_metric: {
  init_script: 'state.messagesList = new ArrayList();',
  map_script: `
    long currentMessageTime = doc['messageReceivedEvent.context.timestamp'].value.millis;
    Map currentMessage = [
      'conversationId': doc['messageReceivedEvent.context.conversationId.keyword'],
      'time': currentMessageTime,
      'intentsPath': doc['brainQueryRequestEvent.brainQueryRequest.user_data.intentsHistoryPath.keyword'].value
    ];
    state.messagesList.add(currentMessage);`,
  combine_script: 'return state',
  reduce_script: `
    List messages = new ArrayList();
    Map conversationsMap = new HashMap();
    Map intentsMap = new HashMap();
    boolean[] ifElseWorkaround = new boolean[1];

    for (state in states) {
      messages.addAll(state.messagesList);
    }

    messages.stream().forEach(message -> {
      Map existingMessage = conversationsMap.get(message.conversationId);
      if(existingMessage == null || message.time > existingMessage.time) {
        conversationsMap.put(message.conversationId, ['time': message.time, 'intentsPath': message.intentsPath]);
      } else {
        ifElseWorkaround[0] = true;
      }
    });

    conversationsMap.entrySet().forEach(conversation -> {
      if (intentsMap.containsKey(conversation.getValue().intentsPath)) {
        long intentsCount = intentsMap.get(conversation.getValue().intentsPath) + 1;
        intentsMap.put(conversation.getValue().intentsPath, intentsCount);
      } else {
        intentsMap.put(conversation.getValue().intentsPath, 1L);
      }
    });

    return intentsMap.entrySet().stream().map(intentPath -> [
      'path': intentPath.getKey().toString(),
      'count': intentPath.getValue()
    ]).collect(Collectors.toSet())`

The answer:

{
    "took": 2,
    "timed_out": false,
    "_shards": {
        "total": 5,
        "successful": 5,
        "skipped": 0,
        "failed": 0
    },
    "hits": {
        "total": {
            "value": 11,
            "relation": "eq"
        },
        "max_score": null,
        "hits": []
    },
    "aggregations": {
        "intentPathsCountAgg": {
            "value": [
                {
                    "smallTalk.greet -> smallTalk.greet2 -> smallTalk.greet3": 2
                },
                {
                    "smallTalk.greet -> smallTalk.greet2 -> smallTalk.greet3  -> smallTalk.greet4": 1
                },
                {
                    "smallTalk.greet -> smallTalk.greet2": 1
                }
            ]
        }
    }
}
Radu Linu
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0

Using script in Terms aggregation we can create buckets on first character of "context.action". Using similar terms sub aggregation we can get all the "context.action" under parent bucket ex A-> A.1->A.1.1 ...

Query:

{
  "size": 0,
  "aggs": {
    "conversations": {
      "terms": {
        "script": {
          "source": "def term=doc['context.action'].value; return term.substring(0,1);" 
--->  returns first character ex A,B,C etc
        },
        "size": 10
      },
      "aggs": {
        "sub_conversations": {
          "terms": {
            "script": {
              "source": "if(doc['context.action'].value.length()>1) return doc['context.action'];"--> All context.action under [A], length check to ignore [A]
            },
            "size": 10
          }
        },
        "count": {
          "cardinality": {
            "script": {
              "source": "if(doc['context.action'].value.length()>1) return doc['context.action'];"--> count of all context.action under A
            }
          }
        }
      }
    }
  }
}

Since in elastic search it not possible to join different documents. you will have to get combined key in client side by iterating over the aggregation bucket.

Result:

  "aggregations" : {
    "conversations" : {
      "doc_count_error_upper_bound" : 0,
      "sum_other_doc_count" : 0,
      "buckets" : [
        {
          "key" : "A",
          "doc_count" : 6,
          "sub_conversations" : {
            "doc_count_error_upper_bound" : 0,
            "sum_other_doc_count" : 0,
            "buckets" : [
              {
                "key" : "A.1",
                "doc_count" : 2
              },
              {
                "key" : "A.1.1",
                "doc_count" : 2
              }
            ]
          },
          "count" : {
            "value" : 2
          }
        },
        {
          "key" : "B",
          "doc_count" : 2,
          "sub_conversations" : {
            "doc_count_error_upper_bound" : 0,
            "sum_other_doc_count" : 0,
            "buckets" : [
              {
                "key" : "B.1",
                "doc_count" : 1
              }
            ]
          },
          "count" : {
            "value" : 1
          }
        }
      ]
    }
  }
jaspreet chahal
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    This is not really what I need. Because of performance, I need to get almost the complete result from elasticsearch. – Radu Linu Mar 12 '20 at 18:19
  • I managed to have a partial result for my problem, but still, there is one issue. Please check this post, in case you have any idea. https://stackoverflow.com/questions/60662222 – Radu Linu Mar 12 '20 at 21:46