3

I have this:

var str = A123B234C456;

I need to split it into comma-separated chunks to return something like this:

A,123,B,234,c,456

I thought a regular expression would be best for this, but I keep getting stuck. Essentially, I tried to do a string replace, but you cannot use a regular expression in the second argument.

I would love to keep it simple and clean and do something like this, but it does not work:

str = str.replace(/[\d]+/, ","+/[\d]+/);

But in the real world that would be too simple.

Is it possible?

Peter Mortensen
  • 30,738
  • 21
  • 105
  • 131
Paul
  • 1,527
  • 2
  • 16
  • 24

3 Answers3

7

It may be more sensible to match the characters and then join them:

str = str.match(/(\d+|[^\d]+)/g).join(',');

But don't omit the quotes when you define the string:

var str = 'A123B234C456';
i alarmed alien
  • 9,412
  • 3
  • 27
  • 40
kennebec
  • 102,654
  • 32
  • 106
  • 127
3

The string split method can be called with a regular expression.

If the regular expression has a capture group, the separator will be kept in the resulting array.

So here you go:

let c = "A123B234C456";
let stringsAndNumbers = c.split(/(\d+)/); // ["A", "123", "B", "234", "C", "456", ""]

Since your example ends with numbers, the last element will be empty. Remove empty array elements:

let stringsAndNumbers = c.split(/(\d+)/).filter(el => el != ""); // ["A", "123", "B", "234", "C", "456"]

Then join:

let stringsAndNumbers = c.split(/(\d+)/).filter(el => el != "").join(","); // "A,123,B,234,C,456"
Peter Mortensen
  • 30,738
  • 21
  • 105
  • 131
nicopowa
  • 459
  • 3
  • 11
0

You can do it by replace() using a regular expression.

For example,

var str = "A123B234C456";
str = str.replace(/([a-bA-B])/g, '$1,');

Now the value of str will be 'A,123,B234,C456'.

Peter Mortensen
  • 30,738
  • 21
  • 105
  • 131
Senad Meškin
  • 13,597
  • 4
  • 37
  • 55