I need help simplifying these boolean algebra functions:
X = !A!BC + A!B!C + !ABC + !AB!C + A!BC
Y = (A!D + !AC)(!B(C + BD))
Z = (!A!C + AD)(B(D + !BC))
The furthest I got with simplifying each equation is:
X = A!B + !AC + !AB!C
Y = A!BC!D + !A!BC
Z = !AB!CD + ABD
If someone could explain how they simplified these functions with steps, that would be appreciated.
