How to to pass optional parameters from one function to another function, which is also a parameter of the first function?

Question

The title seems complicated but the problem itself is easy to describe with an example:

func has another function as a parameter (either my_func1 or my_func2) and I need to provide the parameters to these two function but my_func1 needs three parameters (a,b and c) and my_func2 needs two parameters (a and b). How can I use **kwards in the example? Many thanks!!

def my_func1(a,b,c):
    result = a + b + c
    return result

def my_func2(a,b):
    resultado = a*b
    return resultado

def func(function,a,**kwargs):
    z = function(a,**kwargs)
    return z

test = func(my_func1,3,3 3)

ERROR:
ile "<ipython-input-308-ada7f9588361>", line 1
    prueba = func(my_func1,3,3 3)
                               ^
SyntaxError: invalid syntax

`**kwargs` are key-word arguments, usually named arguments (using dictionaries for example). Have you tried just `*args` for non-key-word arguments?? — KJTHoward, Mar 02 '20 at 15:53

Orsiris de Jong · Answer 1 · 2020-03-02T16:02:15.077

0

I am not sure what you're trying to achieve here, but you should use *args instead of *kwargs since your parameters aren't named.

Here's a working version. Also notice the missing comma in func call arguments.

def my_func1(a,b,c):
    result = a + b + c
    return result

def my_func2(a,b):
    resultado = a*b
    return resultado

def func(function,a,*args):
    z = function(a,*args)
    return z

test = func(my_func1,3,3, 3)
print(test)

edited Mar 02 '20 at 16:02

answered Mar 02 '20 at 15:56

Orsiris de Jong

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Many thanks! I understand now how *args and **kwards work! – JALC Mar 02 '20 at 16:14

score 0 · Answer 2 · answered Mar 02 '20 at 15:57

Looks like a few problems with syntax, for your test:

Did you maybe mean:

test = func(my_func1,3,3, 3)

Notice the missing ,; and then **kwargs should this be: *args?

def my_func1(a,b,c):
    result = a + b + c
    return result

def my_func2(a,b):
    resultado = a*b
    return resultado

def func(function,*args):
    z = function(*args)
    return z

print(func(my_func2,3,3)); # prints 9
print(func(my_func1,3,3,3)); # prints 9

How to to pass optional parameters from one function to another function, which is also a parameter of the first function?

2 Answers2