PHP: try-catch-finally in loop with continue in catch

Question

Ok, just a technical question about the code above:

foreach($x as $y){ // or even a simple for()
    try{
        a();
    } catch(\Exception $e){
        // just skip current iteration
        continue;
    } finally {
        c();
    }
}

Since c() is in the finally block it should be always executed, but what about the continue statement?
According to the documentation it appears to be making the finally block being skipped.

So, does c() be executed in case of a() throwing an exception?

score 2 · Accepted Answer · answered Feb 25 '20 at 09:39

It's simple to discover just using console. Type

php -r 'foreach([1, 2] as $n){try {echo "\n", $n, "\n"; throw new \Exception();} catch (\Exception $e) {continue;} finally {echo "finally has been called";}}'

which is single-string representation of the code

foreach ([1, 2] as $n) {
    try {
        echo "\n", $n, "\n";
        throw new \Exception();
    } catch (\Exception $e) {
        continue;
    } finally {
        echo "finally has been called";
    }
}

you'll get

1
finally has been called
2
finally has been called

PHP: try-catch-finally in loop with continue in catch

1 Answers1