ZSH - Variable Expansion Dilemma

Question

I am using ZSH, and I believe I need to use variable expansion to solve my problem, but I'm not entirely sure.

FOOFIELD=1
PROPERTY=FOO

echo ${(P)PROPERTYFIELD}

Expected Result: 1

Current Result: null

What am I doing wrong?

I've also tried this: `echo ${${PROPERTY}FIELD}` but it yields: `zsh: bad substituion` — 27560, Feb 21 '20 at 20:00

score 1 · Answer 1 · answered Feb 21 '20 at 20:18

1

You can achieve this by executing the below commands

➜  ~   FOOFIELD=1
➜  ~   FOO=11
➜  ~   PROPERTY=FOO
➜  ~   echo ${(P)PROPERTY}
11
➜  ~   echo ${${(P)PROPERTY}FIELD}
1

answered Feb 21 '20 at 20:18

1 Answers1