How to pass multiple parameters with using RxSwift?

Question

I did with below code for passing single parameter.

lazy var priceListData: Observable<FoodPrice> = {
        return self.foodNamesparams1.asObservable()
                   .flatMapLatest(ApiCallViewModel.foodList(_:))
}

But I don't know how to pass multiple parameters..
If I need to pass foodNamesparams1, foodNamesparams2 to ApiCallViewModel.foodList
How can I do it with RxSwift?

foodNamesparams1 and foodNamesparams2 both are BehaviorRelay

check this https://stackoverflow.com/questions/34095592/rxswift-use-zip-with-different-type-observables — Daljeet, Feb 18 '20 at 06:27
This might be helpful: https://medium.com/@danielt1263/recipes-for-combining-observables-in-rxswift-ec4f8157265f — Daniel T., Feb 19 '20 at 00:58

score 0 · Accepted Answer · answered Feb 18 '20 at 10:44

You most likely want to combine the parameters first, most likely via combineLatest or zip.

This will looks something like this

Observable.combineLatest(
    foodNamesparams1.asObservable(),
    foodNamesparams2.asObservable()
  )
  .flatMapLatest(ApiCallViewModel.foodList)

CombineLatest will not emit anything unless both combined observables have emitted at least once - and then it will commit on any update of either combined observable.

Check out the combining section here http://reactivex.io/documentation/operators.html#combining to find the best suited combination method

Oh! I got it! Thank you! :-) – User17373928 Feb 18 '20 at 13:30 — User17373928, Feb 18 '20 at 13:30

How to pass multiple parameters with using RxSwift?

1 Answers1