I have the same question as here: VBA counting multiple duplicates in array , but I haven't found an answer and with my reputation can't leave comment there. I have an array with 150 numbers which could contain repetitive numbers from 1 to 50. Not always there are all 50 numbers in the array. Example of output of what I need: - 10 times: 1, 2; - 20 times: 3, 4 etc; - 0 times: 5, 6, 7 etc. I need to count how many combinations of duplicate numbers it has and what numbers are in those combinations including zero occurrence - which numbers are not in the array. On mentioned above post there are solutions - but only when you know how many combinations of duplicates there are - and I don't know it - there could be 1 (all 150 numbers are equal) - ... - 20 ... up to 50 combinations if it contains all numbers from 1 to 50 three times each. Appreciate any help and advice how to store output - finally it should be written to worksheet in the above mentioned format: [times] - [numbers] (here could be a string, example "5 - 6 - 7").
Here is what I've made for 5 combinations, but do 50 cases and then check 50 strings if they are empty or contain something to write to output is not very good option...
For i = 1 To totalNumbers 'my numbers from 1 to 50 or any other number
numberCount = 0
For j = 0 To UBound(friendsArray) 'my array of any size (in question said 150)
If i = friendsArray(j) Then
numberCount = numberCount + 1
End If
Next j
Select Case numberCount
Case 0
zeroString = zeroString & i & " - "
Case 1
oneString = oneString & i & " - "
Case 2
twoString = twoString & i & " - "
Case 3
threeString = threeString & i & " - "
Case 4
fourString = fourString & i & " - "
Case 5
fiveString = fiveString & i & " - "
Case Else
End Select
Next i