I have searched the web and it gives me a divide answer. Some said it is only an unary operator and some said it is an arithmetic operator. Thanks
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6It's both. Things can be classified as more than one thing. – Kayaman Feb 01 '20 at 10:32
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isn't that the same question as [In Java, is a++ a postfix operator or an unary operator?](https://stackoverflow.com/q/60014618/85421)? – user85421 Feb 01 '20 at 10:56
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@Kayaman I'd argue that it's also an assignment operator, because it assigns a new value to the variable. – Andy Turner Feb 01 '20 at 11:09
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These classifications don't contradict each other.
++ is an unary operator, as it applies to a single operand.
++ is also an arithmetic operator, as it applies to a number and performs an arithmetic operation (incrementing the number by one).
Mureinik
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I think it won't be a mistake to call i++ both Arithmetic and Unary Operator.
However, Oracle doc here distinguishes and classifies ++ as Unary operator.
HoRn
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I can't add anything to the answer. It's just a plain answer to the question asked plainly. Not to say much words, if we dive into [§15.14.2 – 15.15](https://docs.oracle.com/javase/specs/jls/se13/html/jls-15.html#jls-15.14.2) of Oracle Docs, indeed there is a separation between _Postfix_ Increment Operator ++ and Unary Operators. But as the question was about unary _or arithmetic_, my worring of it could be exessive. – HoRn Feb 01 '20 at 12:13
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Then, at last, at the beginning of [§15.15](https://docs.oracle.com/javase/specs/jls/se13/html/jls-15.html#jls-15.15) it's said (in general?): "The operators +, -, ++, --, ~, ! ... are called the unary operators". The term "unary" then seems not so strict to argue about. Then i++ is also arithmetic because, as Mureinik said, simply, it performs an arithmetic operation – HoRn Feb 01 '20 at 12:14