RegEx JS - how to get everything after : and defore / or end of a string

Question

I have a string which looks like this:

/part/:aaaa/:bbbb/some/:cccc

I need to get: aaaa, bbbb, cccc from this string. How can I do it? For now I can get aaaa and bbbb because it between : and /. But how can I get cccc?

To get aaaa and bbbb i use str.match(/:(.*)\//).

Use `/:([^\/]+)/g` and then `rx.exec(str)` in a loop to get Group 1 contents. Or `str.matchAll(/:([^\/]+)/g)` — Wiktor Stribiżew, Jan 29 '20 at 13:39
No need for a regex, use `s.split('/').filter(x => x[0]==":").map(z => z.substring(1))` — Wiktor Stribiżew, Jan 29 '20 at 13:43
@WiktorStribiżew What you are suggesting doesn't look much more appetizing than a regex solution IMHO. — Tim Biegeleisen, Jan 29 '20 at 13:48

score 1 · Accepted Answer · answered Jan 29 '20 at 13:40

1

We can try doing a regex iteration on the pattern :([^\/]+), which would match any colon term, capturing only the portion you want.

var re = /:([^\/]+)/g;
var input = '/part/:aaaa/:bbbb/some/:cccc';
var m;

do {
    m = re.exec(input);
    if (m) {
        console.log(m[1]);
    }
} while (m);

answered Jan 29 '20 at 13:40

Tim Biegeleisen

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Thanks! It works! Will accept answer in 9 minutes. – Nastro Jan 29 '20 at 13:43

RegEx JS - how to get everything after : and defore / or end of a string

1 Answers1